z^2+2z-2=1

Solution for z^2+2z-2=1 equation:

Simplifying
z2 + 2z + -2 = 1

Reorder the terms:
-2 + 2z + z2 = 1

Solving
-2 + 2z + z2 = 1

Solving for variable 'z'.

Reorder the terms:
-2 + -1 + 2z + z2 = 1 + -1

Combine like terms: -2 + -1 = -3
-3 + 2z + z2 = 1 + -1

Combine like terms: 1 + -1 = 0
-3 + 2z + z2 = 0

Factor a trinomial.
(-3 + -1z)(1 + -1z) = 0

Subproblem 1
Set the factor '(-3 + -1z)' equal to zero and attempt to solve:

Simplifying
-3 + -1z = 0

Solving
-3 + -1z = 0

Move all terms containing z to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1z = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1z = 0 + 3
-1z = 0 + 3

Combine like terms: 0 + 3 = 3
-1z = 3

Divide each side by '-1'.
z = -3

Simplifying
z = -3
Subproblem 2
Set the factor '(1 + -1z)' equal to zero and attempt to solve:

Simplifying
1 + -1z = 0

Solving
1 + -1z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1z = 0 + -1
-1z = 0 + -1

Combine like terms: 0 + -1 = -1
-1z = -1

Divide each side by '-1'.
z = 1

Simplifying
z = 1
Solution
z = {-3, 1}